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ENGINEERING TOOLS

CONVEYOR BELT WIDTH CALCULATOR

Select a belt width from required capacity

Given a required throughput, belt speed, material bulk density, surcharge angle and trough geometry, this calculator solves the minimum belt width needed for the load, then rounds up to the nearest standard width and reports how full the cross-section will be.

Required capacity

Cross-section geometry

Result
Minimum width
791
mm
31.2 in
Recommended standard
800
mm
31.5 in
Utilization at standard
97.7
%
1024 t/h max
Formulas
  • b = 0.9·B − 0.05 m (effective belt width, CEMA edge clearance)
  • L = b / 3 (each idler segment)
  • A_trough = L² · sin α · (1 + cos α)
  • A_surcharge = (L · (1 + 2·cos α))² · tan β / 4
  • Q = 3600 · (A_trough + A_surcharge) · v · ρ · 0.85
  • Solve for B, round up to nearest of 500, 650, 800, 1000, 1200, 1400, 1600, 1800, 2000, 2200, 2400 mm

Need a verified belt selection with carcass rating and cover compound?

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How belt width is solved

Required cross-section area follows directly from the target throughput, the belt speed and the bulk density: A = Q / (3600 · v · ρ · filling factor). The filling factor (here 0.85) accounts for edge clearance, surge feed and material settling.

Cross-section area at a given belt width depends on the trough geometry and surcharge angle. We use the CEMA 3-roll equal-length model: three idler segments of length b/3, where b is the effective belt width (0.9·B minus 50 mm edge clearance).

A binary search then solves for the smallest belt width whose cross-section meets the required area. The result is rounded up to the nearest standard width — going wider lowers belt wear and dust generation, never the other way around.

Standard belt widths — indicative capacity

Capacity (t/h) at 35° trough, 20° surcharge, 2.5 m/s belt speed and 0.85 filling factor. Multiply by density / 1.6 for other materials.

Belt widthCapacity @ 1.6 t/m³Typical use
500 mm≈ 150 t/hLight handling, packages
650 mm≈ 280 t/hAggregates, small quarry
800 mm≈ 470 t/hMid-size aggregates / coal
1000 mm≈ 800 t/hGeneral mining and cement
1200 mm≈ 1250 t/hLarge quarry, port loading
1400 mm≈ 1800 t/hHeavy mining, steel mills
1600 mm≈ 2450 t/hIron ore, overland
1800 mm≈ 3200 t/hLarge overland mining
2000 mm≈ 4100 t/hMega-mines, ports
2200 mm≈ 5050 t/hSpecialised heavy duty
2400 mm≈ 6100 t/hIron ore / coal export terminals

Common pitfalls

  • Picking belt width at 100 % utilization. Always size for 70–85 % filling to absorb feed surges and settle lumps without spillage.
  • Confusing volumetric and mass capacity. The same belt at the same speed handles half the t/h if the density drops from 1.6 to 0.8 — wood chips need a much wider belt than iron ore at the same tonnage.
  • Using a steep trough angle to fit a narrower belt. Deeper troughs (45°) raise capacity but increase belt-edge stress and constrain transition-distance design.
  • Ignoring lump size. Even at adequate cross-section, a 1000 mm belt cannot centre 300 mm lumps — minimum width ≈ 3× lump size for rolling stability.
  • Solving width without checking belt speed limits. Some industries cap speed (1.5 m/s for cement, 2.0 m/s for grain) — at those caps the required width balloons quickly.

When to consult an engineer

This calculator returns the geometric belt width for steady-state design. Real installations also require carcass rating, cover compound, splice planning, and head/tail pulley geometry coordinated to the chosen width. For new conveyor design or capacity upgrades that change belt width, talk to a BisonConvey engineer for a verified belt selection.

Get a belt selection

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